Question

Plates of a parallel plate capacitor, having a potential difference $100 \, V$ applied across them, carry a surface charge density of $50 \, nC \, cm^{- 2}$ . Spacing between the plates is

• A. $329 \, \mu m$
• B. $259 \, \mu m$
• C. $177 \, \mu m$
• D. $125 \, \mu m$

Answer 1

Answer: (C)

$E=\frac{\sigma }{\epsilon _{0}}$
Potential difference $V=Ed$
$\therefore d=\frac{V}{E}=\frac{100}{50 \times 10^{- 7}}\times \text{8.85}\times 10^{- 12}=\text{177}\times 10^{- 6}m=177μm$