Photons of energy of 6 texteV are incident on a metal surface whose work function is 4 texteV text. The minimum kinetic energy of the emitted photoelectrons is

Question

Photons of energy of 6 texteV are incident on a metal surface whose work function is 4 texteV text. The minimum kinetic energy of the emitted photoelectrons is (A) Zero (B) 1 texteV (C) 2 texteV (D) 10 texteV

Tardigrade Admin · Accepted Answer

(1/2)mv2=hf-φ0=hf-hf0 The kinetic energy of the emitted photoelectrons is distributed from zero to the maximum value. minimum kinetic energy of emitted photoelectron is zero.

Q. Photons of energy of $6 eV$ are incident on a metal surface whose work function is $4 eV .$ The minimum kinetic energy of the emitted photoelectrons is

Zero

$1 eV$

$2 eV$

$10 eV$

$\frac{1}{2} m v^{2} = h f - ϕ_{0} = h f - h f_{0}$
The kinetic energy of the emitted photoelectrons is distributed from zero to the maximum value.
minimum kinetic energy of emitted photoelectron is zero.

Q. Photons of energy of 6eV are incident on a metal surface whose work function is 4eV. The minimum kinetic energy of the emitted photoelectrons is