Question

Photons of energy of $6 \, \text{eV}$ are incident on a metal surface whose work function is $4 \, \text{eV} \text{.}$ The minimum kinetic energy of the emitted photoelectrons is

• A. Zero
• B. $1 \, \text{eV}$
• C. $2 \, \text{eV}$
• D. $10 \, \text{eV}$

Answer 1

Answer: (A)

$\frac{1}{2}mv^{2}=hf-\phi_{0}=hf-hf_{0}$
The kinetic energy of the emitted photoelectrons is distributed from zero to the maximum value.
minimum kinetic energy of emitted photoelectron is zero.