Phosgene, COCl2 , a poisonous gas decomposes according to the equation COCl2(g)leftharpoons CO(g)+Cl2(g) If Kc=0.083 at 900° C , what is the value of Kc?

Question

Phosgene, COCl2 , a poisonous gas decomposes according to the equation COCl2(g)leftharpoons CO(g)+Cl2(g) If Kc=0.083 at 900° C , what is the value of Kc? (A) 0.125 (B) 8.0 (C) 6.1 (D) 0.16

Tardigrade Admin · Accepted Answer

Kp=Kc(R T)Δ ng where Δ ng=(1 + 1)-1=1,R,=0.082 text L atm mo( textl)- 1K- 1 and T=1173 K So K p = K c ( RT )1=0.083 × 0.082 × 1173 7.98∼ eq8.0

Q. Phosgene, $COC l_{2}$ , a poisonous gas decomposes according to the equation

$COC l_{2} (g) ⇌ CO (g) + C l_{2} (g)$

If $K_{c} = 0.083$ at $90 0^{\circ} C$ , what is the value of $K_{c} ?$

0.125

8.0

6.1

0.16

$K_{p} = K_{c} (RT)^{Δ n_{g}}$

where $Δ n_{g} = (1 + 1) - 1 = 1, R, = 0.082 L atm mo (l)^{- 1} K^{- 1}$ and $T = 1173$ K

So $K_{p} = K_{c} (RT)^{1} = 0.083 \times 0.082 \times 1173$

$7.98 \sim e q 8.0$

Q. Phosgene, COCl2​ , a poisonous gas decomposes according to the equation COCl2​(g)⇌CO(g)+Cl2​(g) If Kc​=0.083 at 900∘C , what is the value of Kc​?

0.125

8.0

6.1

0.16

Kp​=Kc​(RT)Δng​ where Δng​=(1+1)−1=1,R,=0.082 L atm mo(l)−1K−1 and T=1173 K So Kp​=Kc​(RT)1=0.083×0.082×1173 7.98∼eq8.0

Q. Phosgene, $COC l_{2}$ , a poisonous gas decomposes according to the equation

$COC l_{2} (g) ⇌ CO (g) + C l_{2} (g)$

If $K_{c} = 0.083$ at $90 0^{\circ} C$ , what is the value of $K_{c} ?$

$K_{p} = K_{c} (RT)^{Δ n_{g}}$

where $Δ n_{g} = (1 + 1) - 1 = 1, R, = 0.082 L atm mo (l)^{- 1} K^{- 1}$ and $T = 1173$ K

So $K_{p} = K_{c} (RT)^{1} = 0.083 \times 0.082 \times 1173$

$7.98 \sim e q 8.0$