Q. $p H$ of $4.0 g / L N a O H$ solution is

2293 239 Equilibrium Report Error

A

13

55%

B

1

23%

C

4

9%

D

12

14%

Solution:

Molar concentration of $N a O H = \frac{4}{40} = 0.1 M$ $∴ [O H^{-}] = 1 0^{- 1}; [H^{+}] = 1 0^{- 13}; p H = 13$