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Q. $pH$ of $4.0 \,g / L\, NaOH$ solution is

Equilibrium

Solution:

Molar concentration of $NaOH =\frac{4}{40}=0.1\, M$ $\therefore \left[ OH ^{-}\right]=10^{-1} ;\left[ H ^{+}\right]=10^{-13} ; pH =13$