pH of 1 litre solution of strong monobasic acid is 2. Amount of water (in litre) added so that its new pH will becomes 4 is

Question

pH of 1 litre solution of strong monobasic acid is 2. Amount of water (in litre) added so that its new pH will becomes 4 is (A) 10 (B) 100 (C) 1000 (D) 99

Tardigrade Admin · Accepted Answer

V1 = 1 L,M1 = 10-2 M2 = 10-4,V2 = ? V2 = (10-2× 1/10-4)=100 lit ∴ VH2Oadded = 100 -1 =99 lit

Q. pH of 1 litre solution of strong monobasic acid is 2. Amount of water (in litre) added so that its new pH will becomes 4 is

10

100

1000

99

$V_{1} = 1 L, M_{1} = 1 0^{- 2}$
$M_{2} = 1 0^{- 4}, V_{2} = ?$
$V_{2} = \frac{1 0 ^{- 2} \times 1}{1 0 ^{- 4}} = 100 l i t$
$∴ V_{H_{2} O} a dd e d = 100 - 1 = 99 l i t$

Q. pH of 1 litre solution of strong monobasic acid is 2. Amount of water (in litre) added so that its new pH will becomes 4 is

10

100

1000

99

V1​=1L,M1​=10−2 M2​=10−4,V2​=? V2​=10−410−2×1​=100lit ∴VH2​O​added=100−1=99lit

$V_{1} = 1 L, M_{1} = 1 0^{- 2}$
$M_{2} = 1 0^{- 4}, V_{2} = ?$
$V_{2} = \frac{1 0 ^{- 2} \times 1}{1 0 ^{- 4}} = 100 l i t$
$∴ V_{H_{2} O} a dd e d = 100 - 1 = 99 l i t$