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  4. pH of 1 litre solution of strong monobasic acid is 2. Amount of water (in litre) added so that its new pH will becomes 4 is

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Q. pH of 1 litre solution of strong monobasic acid is 2. Amount of water (in litre) added so that its new pH will becomes 4 is

Solution:

$V_1 \,=\,1 \,L,M_1\, =\,10^{-2}$
$M_2 \,=\,10^{-4},V_2 = ?$
$V_2 = \frac {10^{-2}\times 1}{10^{-4}}=100\,lit$
$\therefore V_{H_2O}added = 100 -1 =99\,lit$