Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
PH of 0.2 M sodium acetate solution is ( pK a . of CH 3 COOH is .4.74)
Q. PH of
0.2
M
sodium acetate solution is
(
p
K
a
of
C
H
3
COO
H
is
4.74
)
2905
260
Report Error
A
8.5
100%
B
11
0%
C
9.7
0%
D
9
0%
Solution:
p
H
=
5
1
[
p
K
w
+
p
k
a
+
lo
g
C
]
=
2
1
[
14
+
4.374
+
lo
g
0.2
]
=
2
1
[
18.74
−
0.699
]
=
9