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  4. PH of 0.2 M sodium acetate solution is ( pK a . of CH 3 COOH is .4.74)

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Q. PH of $0.2\, M$ sodium acetate solution is $\left( pK _{ a }\right.$ of $CH _{3} COOH$ is $\left.4.74\right)$

Solution:

$p H=\frac{1}{5}\left[p K_{w}+p k_{a}+\log C\right]$
$=\frac{1}{2}[14+4.374+\log 0.2]$
$=\frac{1}{2}[18.74-0.699]=9$