Question

Permanganate $(VII)$ ion, $Mn{O}_4^{-}$ oxidises $I^{-}$ ion to $I_2$ and gives manganese $(IV)$ oxide $Mn{O}_2$ in basic medium. The skeletal ionic equation is given as
$pMn{O}_{4\left(aq\right)}^{-}+q{I}_{\left(aq\right)}^{-}+x{H}_2{O}_{\left(l\right)}^{}\to rMn{O}_{2\left(s\right)}+s{I}_2+yO{H}_{\left(aq\right)}^{-}$
The values of $p$, $q$, $r$ and $s$ are

	p	q	r	s
(a)	1	2	8	4
(b)	2	6	2	3
(c)	2	4	2	8
(d)	1	4	8	2

• A. a
• B. b
• C. c
• D. d

Answer 1

Answer: (B)

$2Mn{O}_{4\left(aq\right)}^{-}+6I_{\left(aq\right)}^{-}+4H_{2}O\left(l\right)\to 2Mn{O}_{2\left(s\right)}+3I_{2\left(s\right)}+8O{H}_{\left(aq\right)}^{-}$