Percentage of Se (at. mass =78.4 ) in peroxidase anhydrase enzyme is 0.5 % by weight, then minimum molecular mass of peroxidase anhydrase enzyme is

Question

Percentage of Se (at. mass =78.4 ) in peroxidase anhydrase enzyme is 0.5 % by weight, then minimum molecular mass of peroxidase anhydrase enzyme is (A) 1.568 × 103 (B) 15.68 (C) 2.168 × 104 (D) 1.568 × 104

Tardigrade Admin · Accepted Answer

Suppose the molecular weight of enzyme =x 0.5 % by weight means in 100 g of enzyme weight of Se =0.5 g ∴ In xg of enzyme weight of Se (0.5/100) × x Hence, 78.4=(0.5 × x/100) ∴ x=15680=1.568 × 104

Q. Percentage of Se (at. mass $= 78.4$ ) in peroxidase anhydrase enzyme is $0.5%$ by weight, then minimum molecular mass of peroxidase anhydrase enzyme is

$1.568 \times 1 0^{3}$

$15.68$

$2.168 \times 1 0^{4}$

$1.568 \times 1 0^{4}$

Suppose the molecular weight of enzyme $= x$
$0.5%$ by weight means in $100 g$ of enzyme weight of $S e = 0.5 g$
$∴$ In $xg$ of enzyme weight of $S e \frac{0.5}{100} \times x$
Hence, $78.4 = \frac{0.5 \times x}{100}$
$∴ x = 15680 = 1.568 \times 1 0^{4}$

Q. Percentage of Se (at. mass =78.4 ) in peroxidase anhydrase enzyme is 0.5% by weight, then minimum molecular mass of peroxidase anhydrase enzyme is

1.568×103

15.68

2.168×104

1.568×104