Question

Percentage of Se (at. mass $=78.4$ ) in peroxidase anhydrase enzyme is $0.5 \%$ by weight, then minimum molecular mass of peroxidase anhydrase enzyme is

• A. $1.568 \times 10^3$
• B. $15.68$
• C. $2.168 \times 10^4$
• D. $1.568 \times 10^4$

Answer 1

Answer: (D)

Suppose the molecular weight of enzyme $=x$
$0.5 \%$ by weight means in $100\, g$ of enzyme weight of $Se =0.5 \, g$
$\therefore$ In $xg$ of enzyme weight of $Se \frac{0.5}{100} \times x$
Hence, $78.4=\frac{0.5 \times x}{100}$
$\therefore x=15680=1.568 \times 10^{4}$