Tardigrade
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Tardigrade
Question
Chemistry
P ->[1.CH3MgBr][2.H3O+] R ->[1.dil.NaOH][2.Δ] 4-methylpent-3-en-2-one P is
Q.
P
1.C
H
3
MgBr
2.
H
3
O
+
R
1.dil.NaOH
2.
Δ
4-methylpent-3-en-2-one
P
is
4805
211
KCET
KCET 2014
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A
ethanaimine
13%
B
ethanal
33%
C
propane
27%
D
ethanenitrile
27%
Solution:
Ethane nitrile on reaction with
C
H
3
M
g
B
r
followed by hydrolysis produced acetone which on reaction with dil. NaOH undergo aldol condensation to produce 4-methyl pent-3-ene-2-one as shown below