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Tardigrade
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Chemistry
P ->[1.CH3MgBr][2.H3O+] R ->[1.dil.NaOH][2.Δ] 4-methylpent-3-en-2-one P is
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Q. $\ce { P ->[{1.CH_3MgBr}][{2.H_3O^+}] R ->[{1.dil.NaOH}][{2.\Delta}] }$ 4-methylpent-3-en-2-one $P$ is
KCET
KCET 2014
A
ethanaimine
13%
B
ethanal
33%
C
propane
27%
D
ethanenitrile
27%
Solution:
Ethane nitrile on reaction with $CH _{3} MgBr$ followed by hydrolysis produced acetone which on reaction with dil. NaOH undergo aldol condensation to produce 4-methyl pent-3-ene-2-one as shown below