Question

Oxidation state of Mn in the compound formed by alkaline oxidative fusion of $Mn{O}_2$ by KOH is:-

• A. 4
• B. 5
• C. 6
• D. 7

Answer 1

Answer: (C)

$\stackrel{\text{+4}}{\mathrm{Mn}}{\text{O}}_{\text{2}}\frac{\text{ alkaline }}{\text{ oxidative }}$ ${\text{MnO}}_{\text{4}}^{2-}$ Fusion

By the alkaline oxidative fusion of $Mn{O}_2$ by $KOH$ the product formed is $Mn{O}_4^{2-}$

-2 = $\text{x + 4}\left(-2\right)$

$\text{x = }6$