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  4. Oxidation state of Mn in the compound formed by alkaline oxidative fusion of MnO2 by KOH is:-

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Q. Oxidation state of Mn in the compound formed by alkaline oxidative fusion of $MnO_{2}$ by KOH is:-

NTA AbhyasNTA Abhyas 2020The d-and f-Block Elements

Solution:

$\overset{\text{+4}}{\text{Mn}}\text{O}_{\text{2}}\frac{\text{ alkaline }}{\text{ oxidative }}$ $\text{MnO}_{\text{4}} ^{2 -}$ Fusion

By the alkaline oxidative fusion of $MnO_{2}$ by $KOH$ the product formed is $MnO_{4}^{2 -}$

-2 = $\text{x + 4} \, \left(- 2\right)$

$\text{x = }6$