Oxidation number of S in H2S2O8 is

Question

Oxidation number of S in H2S2O8 is (A) +2 (B) +4 (C) +3 (D) +6

Tardigrade Admin · Accepted Answer

The structure of H 2 S 2 O 8 is as <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/ca72d8df92763b3bb6ac81d3543eb359-.png" /> It contains peroxide linkage due to which the oxidation number of these two oxygen atoms will be -1 each. 2 ×(+1)+2 x +6 ×(-2)+2(-1)=0 2+2 x-12-2=0 or 2 x=12 ∵ x=+6

Q. Oxidation number of $S$ in $H_{2} S_{2} O_{8}$ is

+2

+4

+3

+6

The structure of $H_{2} S_{2} O_{8}$ is as

It contains peroxide linkage due to which the oxidation number of these two oxygen atoms will be $- 1$ each.
$2 \times (+ 1) + 2 x + 6 \times (- 2) + 2 (- 1) = 0$
$2 + 2 x - 12 - 2 = 0$
or $2 x = 12$
$∵ x = + 6$

Q. Oxidation number of S in H2​S2​O8​ is

+2

+4

+3

+6

The structure of H2​S2​O8​ is as It contains peroxide linkage due to which the oxidation number of these two oxygen atoms will be −1 each. 2×(+1)+2x+6×(−2)+2(−1)=0 2+2x−12−2=0 or 2x=12 ∵x=+6

Q. Oxidation number of $S$ in $H_{2} S_{2} O_{8}$ is

The structure of $H_{2} S_{2} O_{8}$ is as

It contains peroxide linkage due to which the oxidation number of these two oxygen atoms will be $- 1$ each.
$2 \times (+ 1) + 2 x + 6 \times (- 2) + 2 (- 1) = 0$
$2 + 2 x - 12 - 2 = 0$
or $2 x = 12$
$∵ x = + 6$