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Q. Oxidation number of $S$ in $ H_{2}S_{2}O_{8}$ is

ManipalManipal 2009Redox Reactions

Solution:

The structure of $H _{2} S _{2} O _{8}$ is as
image
It contains peroxide linkage due to which the oxidation number of these two oxygen atoms will be $-1$ each.
$2 \times(+1)+2 x +6 \times(-2)+2(-1)=0$
$2+2 x-12-2=0$
or $2 x=12$
$\because x=+6$