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Tardigrade
Question
Chemistry
Oxidation number of iodine in IO3-, IO4-, KI and I2 respectively is
Q. Oxidation number of iodine in
I
O
3
−
,
I
O
4
−
,
K
I
and
I
2
respectively is
2456
192
Redox Reactions
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A
-2, -5, -1, 0
4%
B
+5, +7, -1, 0
89%
C
+2, +5, +1, 0
5%
D
- 1, +1, 0, +1
2%
Solution:
I
O
3
−
→
x
+
3
(
−
2
)
=
−
1
⇒
x
=
+
5
I
O
4
−
→
x
+
4
(
−
2
)
=
−
1
⇒
x
=
+
7
K
I
→
+
1
+
x
=
0
⇒
x
=
−
1
I
2
→
0
⇒
x
=
0