1. Tardigrade
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  3. Chemistry
  4. Oxidation number of iodine in IO3-, IO4-, KI and I2 respectively is

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Q. Oxidation number of iodine in $IO_3^-$, $IO_4^-$, $KI$ and $I_2$ respectively is

Redox Reactions

Solution:

$IO_{3}^{-} \to x + 3\left(-2\right) = -1 \Rightarrow x = + 5$
$IO_{4}^{-} \to x + 4\left(-2\right) = -1 \Rightarrow x = +7$
$KI \to + 1 + x = 0 \Rightarrow x = -1$
$I_{2} \to 0 \Rightarrow x = 0$