Oxidation number o f Cr in [ Cr ( CO )6] is

Question

Oxidation number o f Cr in [ Cr ( CO )6] is (A) +6 (B) -6 (C) +3 (D) 0

Tardigrade Admin · Accepted Answer

CO (carbonyl) is a neutral ligand. So, oxidation number of the metal is metal carbonyl compounds will be 0 (zero). [ overset0Cr ( CO )6]: Hexacarbonyl chromium (0)

Q. Oxidation number o $f C r$ in $[C r (CO)_{6}]$ is

+6

-6

+3

0

$CO$ (carbonyl) is a neutral ligand. So, oxidation number of the metal is metal carbonyl compounds will be 0 (zero).
$[C 0 r (CO)_{6}] :$ Hexacarbonyl chromium $(0)$

Q. Oxidation number o fCr in [Cr(CO)6​] is

+6

-6

+3

0

CO (carbonyl) is a neutral ligand. So, oxidation number of the metal is metal carbonyl compounds will be 0 (zero). [C0r(CO)6​]: Hexacarbonyl chromium (0)

Q. Oxidation number o $f C r$ in $[C r (CO)_{6}]$ is

$CO$ (carbonyl) is a neutral ligand. So, oxidation number of the metal is metal carbonyl compounds will be 0 (zero).
$[C 0 r (CO)_{6}] :$ Hexacarbonyl chromium $(0)$