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  4. Oxidation number o f Cr in [ Cr ( CO )6] is

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Q. Oxidation number o $f Cr$ in $\left[ Cr ( CO )_{6}\right]$ is

AP EAMCETAP EAMCET 2020

Solution:

$CO$ (carbonyl) is a neutral ligand. So, oxidation number of the metal is metal carbonyl compounds will be 0 (zero).
$\left[\overset{0}{C}r ( CO )_{6}\right]:$ Hexacarbonyl chromium $(0)$