One mole of P4O10 is allowed to react fully with dust and salt-free doubly distilled water and the volume is made up to 1 L. What is the normality of the so-generated orthophosphoric acid? P4O10 +6 H2O → 4H3 PO4

Question

One mole of P4O10 is allowed to react fully with dust and salt-free doubly distilled water and the volume is made up to 1 L. What is the normality of the so-generated orthophosphoric acid? P4O10 +6 H2O → 4H3 PO4 (A) 1.0 N (B) 8.0 N (C) 12.0 N (D) 4.0 N

Tardigrade Admin · Accepted Answer

underset1 molP 4 O 10+6 H 2 O → underset4 mol4 H 3 PO 4 Thus, 4 moles of orthophosphoric acid are generated in 1 L solution. ∴ Molarity =4 M and normality = molarity × basicity =4 × 3=12.0 N

Q. One mole of $P_{4} O_{10}$ is allowed to react fully with dust and salt-free doubly distilled water and the volume is made up to $1 L$ . What is the normality of the so-generated orthophosphoric acid?
$P_{4} O_{10} + 6 H_{2} O \to 4 H_{3} P O_{4}$

$1.0 N$

$8.0 N$

$12.0 N$

$4.0 N$

$1 m o l P_{4} O_{10} + 6 H_{2} O \to 4 m o l 4 H_{3} P O_{4}$

Thus, 4 moles of orthophosphoric acid are generated in $1 L$ solution.

$∴$ Molarity $= 4 M$

and normality $=$ molarity $\times$ basicity $= 4 \times 3 = 12.0 N$

Q. One mole of P4​O10​ is allowed to react fully with dust and salt-free doubly distilled water and the volume is made up to 1L. What is the normality of the so-generated orthophosphoric acid? P4​O10​+6H2​O→4H3​PO4​

1.0N

8.0N

12.0N

4.0N