Question

One mole of $N_2{H}_4$ loses $10$ moles of electrons to form a new compound, $y$. Assuming that all nitrogen appear in the new compound, what is the oxidation state of nitrogen in $y$ (there is no change in the oxidation state of hydrogen)?

Answer 1

Answer: 3

$N_2{H}_4\stackrel{\text{loss of}{}_{10}\mathrm{e}{}^{-}}{\to }Y$
Oxidation number of nitrogen in the question $N_2{O}_4=-2$
According to given information in the question
$N_2{H}_4\to N_2$
$\therefore Y=N_2$
Oxidation number of nitrogen in compound
$Y=+3$