1. Tardigrade
  2. Question
  3. Chemistry
  4. One mole of N2H4 loses 10 moles of electrons to form a new compound, y. Assuming that all nitrogen appear in the new compound, what is the oxidation state of nitrogen in y (there is no change in the oxidation state of hydrogen)?

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Q. One mole of $N_{2}H_{4}$ loses $10$ moles of electrons to form a new compound, $y$. Assuming that all nitrogen appear in the new compound, what is the oxidation state of nitrogen in $y$ (there is no change in the oxidation state of hydrogen)?

Redox Reactions

Solution:

$N_{2}H_{4} \xrightarrow{ {\text{loss of}} \,10e^{-}}Y$
Oxidation number of nitrogen in the question $N_2O_4 =-2$
According to given information in the question
$N_{2}H_{4} \to N_{2}$
$\therefore Y=N_{2}$
Oxidation number of nitrogen in compound
$Y=+3$