One mole of fluorine is reacted with two moles of hot and concentrated KOH. The product formed are KF,H2O and O2 The molar ratio of KF, H2O and O2 is respectively

Question

One mole of fluorine is reacted with two moles of hot and concentrated KOH. The product formed are KF,H2O and O2 The molar ratio of KF, H2O and O2 is respectively (A) 1: 1: 2 (B) 2: 1: 0.5 (C) 1: 2: 1 (D) 2: 1: 2

Tardigrade Admin · Accepted Answer

F2+2 KOH → 2KF+H2O+1/2O2 ∴ Molar ratio of KF: H2: O2 from balanced chemical equation is 2:1:0.5(1/2)

Q. One mole of fluorine is reacted with two moles of hot and concentrated KOH. The product formed are KF, $H_{2} O$ and $O_{2}$ The molar ratio of KF, $H_{2} O$ and $O_{2}$ is respectively

1 : 1 : 2

2 : 1 : 0.5

1 : 2 : 1

2 : 1 : 2

$F_{2} + 2 K O H \to 2 K F + H_{2} O + 1/2 O_{2}$
$∴$ Molar ratio of $K F : H_{2} : O_{2}$ from balanced chemical equation is $2 : 1 : 0.5 (1/2)$

Q. One mole of fluorine is reacted with two moles of hot and concentrated KOH. The product formed are KF,H2​O and O2​ The molar ratio of KF, H2​O and O2​ is respectively