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  4. One mole of fluorine is reacted with two moles of hot and concentrated KOH. The product formed are KF,H2O and O2 The molar ratio of KF, H2O and O2 is respectively

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Q. One mole of fluorine is reacted with two moles of hot and concentrated KOH. The product formed are KF,$H_2O$ and $O_2$ The molar ratio of KF, $H_2O$ and $O_2$ is respectively

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Solution:

$F_{2}+2\,KOH \to 2KF+H_{2}O+1/2O_{2}$
$\therefore $ Molar ratio of $KF : H_{2}: O_{2}$ from balanced chemical equation is $2:1:0.5(1/2)$