One mole of an ideal gas is expanded isothermally and reversibly to half of its initial pressure. AS for the process in J K-1 mol-1 is [ℓn 2 = 0.693 and = 8.314, J/(mol K)]

Question

One mole of an ideal gas is expanded isothermally and reversibly to half of its initial pressure. AS for the process in J K-1 mol-1 is [ℓn 2 = 0.693 and = 8.314, J/(mol K)] (A) 6.76 (B) 5.76 (C) 10.76 (D) 8.03

Tardigrade Admin · Accepted Answer

For isothermal process (Δ T = 0) Δ S = R ℓ n (P1/P2) = 8.314 ℓ n 2 = 8.314× 0.693 = 5.76 JK-1 mol-1

Q. One mole of an ideal gas is expanded isothermally and reversibly to half of its initial pressure. AS for the process in $J K^{- 1} m o l^{- 1}$ is
[ $ℓ$ n 2 = 0.693 and = 8.314, J/(mol K)]

6.76

5.76

10.76

8.03

For isothermal process $(Δ T = 0)$
$Δ S = R ℓ n \frac{P _{1}}{P _{2}} = 8.314 ℓ n 2$
$= 8.314 \times 0.693 = 5.76 J K^{- 1} m o l^{- 1}$

Q. One mole of an ideal gas is expanded isothermally and reversibly to half of its initial pressure. AS for the process in JK−1mol−1 is [ℓn 2 = 0.693 and = 8.314, J/(mol K)]