One litre of carbonated water is prepared by dissolving CO2 gas at a pressure of 2.4 atm in 1kg water in the bottling process at 25° C.KH of CO2 in water is 4× 104atm at 25° C. Find the mass of dissolved CO2 in mg (Round off answer to the nearest integer)

Question

One litre of carbonated water is prepared by dissolving CO2 gas at a pressure of 2.4 atm in 1kg water in the bottling process at 25° C.KH of CO2 in water is 4× 104atm at 25° C. Find the mass of dissolved CO2 in mg (Round off answer to the nearest integer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

p=KH⋅ X 2.4=4× 104× (nCO2/nCO2 + (1000)18)≈4× 104× (nCO2/1000 / 18) nCO2=(10/3)× 10- 3 nCO2=(10/3)× 10- 3× 44gm=146.67mg

Q. One litre of carbonated water is prepared by dissolving CO2​ gas at a pressure of 2.4 atm in 1kg water in the bottling process at 25∘C.KH​ of CO2​ in water is 4×104atm at 25∘C. Find the mass of dissolved CO2​ in mg (Round off answer to the nearest integer)

p=KH​⋅X 2.4=4×104×nCO2​​+181000​nCO2​​​≈4×104×1000/18nCO2​​​ nCO2​​=310​×10−3 nCO2​​=310​×10−3×44gm=146.67mg

$p = K_{H} \cdot X$
$2.4 = 4 \times 1 0^{4} \times \frac{n _{C O_{2}}}{n _{C O_{2}} + \frac{1000}{18}} \approx 4 \times 1 0^{4} \times \frac{n _{C O_{2}}}{1000/18}$
$n_{C O_{2}} = \frac{10}{3} \times 1 0^{- 3}$
$n_{C O_{2}} = \frac{10}{3} \times 1 0^{- 3} \times 44 g m = 146.67 m g$