Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
One gram of oxygen at NTP occupies the volume :
Q. One gram of oxygen at NTP occupies the volume :
3238
232
AFMC
AFMC 2000
Report Error
A
0.7 L
B
4.8 L
C
1.4 L
D
1.2 L
Solution:
1
mole of substance
≡
its molecular mass
≡
22.4
L
32
g
of
O
2
=
22.4
L
(
m
o
l
. mass of
O
2
=
32
)
⇒
1
g
O
2
=
32
22.4
=
0.7
L