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  4. One gram of oxygen at NTP occupies the volume :

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Q. One gram of oxygen at NTP occupies the volume :

AFMCAFMC 2000

Solution:

$1$ mole of substance $\equiv$ its molecular mass
$\equiv 22.4\, L$
$32 g$ of $O _{2}=22.4 L $
$\left( mol\right.$. mass of $\left.O _{2}=32\right)$
$\Rightarrow 1\, g\, O _{2}=\frac{22.4}{32}=0.7 \,L$