Question

One gram of oxygen at NTP occupies the volume :

• A. 0.7 L
• B. 4.8 L
• C. 1.4 L
• D. 1.2 L

Answer 1

Answer: (A)

$1$ mole of substance $\equiv$ its molecular mass
$\equiv 22.4L$
$32g$ of $O_2=22.4L$
$(mol$. mass of $O_2=32)$
$\Rightarrow 1g{O}_2=\frac{22.4}{32}=0.7L$