On treatment of [Pt(NH3)4]2+ with concentrated HCl, two compounds (I) and (II) having the same formula, [Pt(NH3)2Cl2] are obtained, (I) can be converted into (II) by boiling with dilute HCl. A solution of (I) reacts with oxalic acid to form [Pt(NH3)2(C2O4)] whereas (II) does not react. Point out the correct statement of the following.

Question

On treatment of [Pt(NH3)4]2+ with concentrated HCl, two compounds (I) and (II) having the same formula, [Pt(NH3)2Cl2] are obtained, (I) can be converted into (II) by boiling with dilute HCl. A solution of (I) reacts with oxalic acid to form [Pt(NH3)2(C2O4)] whereas (II) does not react. Point out the correct statement of the following. (A) (I) cis, (II) trans; both tetrahedral (B) (I) cis, (II) trans; both square planar (C) (I) trans, (II) cis; both tetrahedral (D) (I) trans, (II) cis; both square planar

Tardigrade Admin · Accepted Answer

Chelate ligands i.e. oxalato being too small to span the trans positions and thus prefer to occupy the cis-position. So (I) is cis and (II) is trans. Platinum is in +2 oxidation state with 5d8 valence shell electron configuration. This configuration has higher CFSE and thus favours square planar geometry.