1. Tardigrade
  2. Question
  3. Chemistry
  4. On treatment of [Pt(NH3)4]2+ with concentrated HCl, two compounds (I) and (II) having the same formula, [Pt(NH3)2Cl2] are obtained, (I) can be converted into (II) by boiling with dilute HCl. A solution of (I) reacts with oxalic acid to form [Pt(NH3)2(C2O4)] whereas (II) does not react. Point out the correct statement of the following.

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Q. On treatment of $[Pt(NH_{3})_{4}]^{2+}$ with concentrated $HCl$, two compounds (I) and (II) having the same formula, $[Pt(NH_{3})_{2}Cl_{2}] $ are obtained, (I) can be converted into (II) by boiling with dilute $HCl$. A solution of (I) reacts with oxalic acid to form $[Pt(NH_{3})_{2}(C_{2}O_{4})]$ whereas (II) does not react. Point out the correct statement of the following.

Coordination Compounds

Solution:

Chelate ligands i.e. oxalato being too small to span the trans positions and thus prefer to occupy the cis-position. So (I) is cis and (II) is trans. Platinum is in +2 oxidation state with 5d8 valence shell electron configuration. This configuration has higher CFSE and thus favours square planar geometry.