Q.
On the horizontal surface of a truck a block of mass 1kg is placed (μ=0.6) and truck is moving with acceleration 5m/sec2 then the frictional force on the block will be
frl=μsN=μs×mg=0.6×1×10=6N.
where frl is the force of limiting friction.
Pseudo force =ma=1×5;F=5N
If F<frl, block does not move. So static friction is present.
Static friction = applied force . ∴fr=5N.