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Q. On the horizontal surface of a truck a block of mass $1 \,kg$ is placed $(\mu = 0.6)$ and truck is moving with acceleration $5\, m/\sec^2$ then the frictional force on the block will be

AIPMTAIPMT 2001Laws of Motion

Solution:

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$f_{rl}=\mu_sN=\mu_s\times mg=0.6\times1\times10=6 N.$
where $f_{rl}$ is the force of limiting friction.
Pseudo force $=ma = 1\times 5 ; F = 5\, N$
If $F < f_{rl}$, block does not move. So static friction is present.
Static friction = applied force .
$\therefore f_r=5\, N$.