On the basis of the following thermochemical data [ΔfG°H+(aq)=0] H2O(l)→ H+(aq)+OH-(aq);Δ H=57.32 kJ H2(g)+(1/2)O2(g)→ H2O(l); Δ H=-286.02 kJ The value of enthalpy of formation of OH- ion at 25°C is

Question

On the basis of the following thermochemical data [ΔfG°H+(aq)=0] H2O(l)→ H+(aq)+OH-(aq);Δ H=57.32 kJ H2(g)+(1/2)O2(g)→ H2O(l); Δ H=-286.02 kJ The value of enthalpy of formation of OH- ion at 25°C is (A) -22.88 kJ (B) -228.88 kJ (C) +228.88 kJ (D) -343.52 kJ

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Consider the heat of formation of H2O <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/73b3cb82239d206d9597c98f7a3c49f9-.png" />

Q. On the basis of the following thermochemical data
$[Δ_{f} G^{\circ} H^{+} (a q) = 0]$
$H_{2} O (l) \to H^{+} (a q) + O H^{-} (a q); Δ H = 57.32 k J$
$H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l); Δ H = - 286.02 k J$
The value of enthalpy of formation of $O H^{-}$ ion at $2 5^{\circ} C$ is

$- 22.88 k J$

$- 228.88 k J$

$+ 228.88 k J$

$- 343.52 k J$

Consider the heat of formation of $H_{2} O$

Q. On the basis of the following thermochemical data [Δf​G∘H+(aq)=0] H2​O(l)→H+(aq)+OH−(aq);ΔH=57.32kJ H2​(g)+21​O2​(g)→H2​O(l);ΔH=−286.02kJ The value of enthalpy of formation of OH− ion at 25∘C is

−22.88kJ

−228.88kJ

+228.88kJ

−343.52kJ

Consider the heat of formation of H2​O

$- 22.88 k J$

$- 228.88 k J$

$+ 228.88 k J$

$- 343.52 k J$

Consider the heat of formation of $H_{2} O$