1. Tardigrade
  2. Question
  3. Chemistry
  4. On the basis of the following thermochemical data [ΔfG°H+(aq)=0] H2O(l)→ H+(aq)+OH-(aq);Δ H=57.32 kJ H2(g)+(1/2)O2(g)→ H2O(l); Δ H=-286.02 kJ The value of enthalpy of formation of OH- ion at 25°C is

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Q. On the basis of the following thermochemical data
$\left[\Delta_{f}G^{\circ}H^{+}\left(aq\right)=0\right]$
$H_{2}O\left(l\right)\to H^{+}\left(aq\right)+OH^{-}\left(aq\right);\Delta H=57.32 kJ$
$H_{2}\left(g\right)+\frac{1}{2}O_{2}\left(g\right)\to H_{2}O\left(l\right); \Delta H=-286.02 kJ$
The value of enthalpy of formation of $OH^{-}$ ion at $25^{\circ}C $ is

Thermodynamics

Solution:

Consider the heat of formation of $H_2O$
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