On mixing 20 mL of acetone with 60 mL of chloroform, the total volume of the solution is

Question

On mixing 20 mL of acetone with 60 mL of chloroform, the total volume of the solution is (A) less than 80 mL  (B) more than 80 mL  (C) equal to 80 mL  (D) unpredictable

Tardigrade Admin · Accepted Answer

A mixture of chloroform (CHCl3) and aceton (CH3)2CO shows negative deviations from Raoult’s law due to formation of hydrogen bonding between the two molecules. Hence, a slight decrease in volume takes place <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/3e8757ba48b685ae3690e41c0be5bb0c-.jpeg" />

Q. On mixing $20 m L$ of acetone with $60 m L$ of chloroform, the total volume of the solution is

less than $80 m L$

more than $80 m L$

equal to $80 m L$

unpredictable

A mixture of chloroform $(C H C l_{3})$ and aceton $(C H_{3})_{2} CO$ shows negative deviations from Raoult’s law due to formation of hydrogen bonding between the two molecules. Hence, a slight decrease in volume takes place

Q. On mixing 20mL of acetone with 60mL of chloroform, the total volume of the solution is

less than 80mL

more than 80mL

equal to 80mL