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  4. On mixing 20 mL of acetone with 60 mL of chloroform, the total volume of the solution is

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Q. On mixing $ 20\, mL $ of acetone with $ 60\, mL $ of chloroform, the total volume of the solution is

J & K CETJ & K CET 2019Solutions

Solution:

A mixture of chloroform $(CHCl_{3})$ and aceton $(CH_{3})_{2}CO$ shows negative deviations from Raoult’s law due to formation of hydrogen bonding between the two molecules. Hence, a slight decrease in volume takes place
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