On mixing 10 mL of acetone with 40 mL of chloroform, the total volume of the solution is

Question

On mixing 10 mL of acetone with 40 mL of chloroform, the total volume of the solution is (A) < 50 mL (B) > 50 mL (C) = 50 mL (D) cannot be predicted

Tardigrade Admin · Accepted Answer

On mixing 10 mL of acetone with 40 mL of chloroform, the total volume of the solution is < 50 mL as the interparticle forces in between

C H C l_{3}

and acetone increases due to H-bonding and thus,

Δ V

mixing = -ve.
Chloroform and acetone hence form solution with negative deviation.

Q. On mixing 10 mL of acetone with 40 mL of chloroform, the total volume of the solution is