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  4. On mixing 10 mL of acetone with 40 mL of chloroform, the total volume of the solution is

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Q. On mixing 10 mL of acetone with 40 mL of chloroform, the total volume of the solution is

NTA AbhyasNTA Abhyas 2020Solutions

Solution:

On mixing 10 mL of acetone with 40 mL of chloroform, the total volume of the solution is < 50 mL as the interparticle forces in between $CHCl_{3}$ and acetone increases due to H-bonding and thus,

$\Delta V$ mixing = -ve.
Chloroform and acetone hence form solution with negative deviation.