On heating, lead(II) nitrate gives a brown gas (A). The gas (A) on cooling changes to a colourless solid/liquid (B). (B) on heating with NO changes to a blue solid (C). The oxidation number of nitrogen in solid (C) is :

Question

On heating, lead(II) nitrate gives a brown gas (A). The gas (A) on cooling changes to a colourless solid/liquid (B). (B) on heating with NO changes to a blue solid (C). The oxidation number of nitrogen in solid (C) is : (A) +5 (B) +2 (C) +4 (D) +3

Tardigrade Admin · Accepted Answer

Pb(NO3)2 xrightarrowΔ PbO + underset overset textBrown gas(A)2NO2 + (1/2)O2(g) NO2(g) xrightarrow textCooling underset(B)N2O4 N2O4 + NO xrightarrowΔ underset overset textBlue Solid(C)N2O3 O.S. of nitrogen in N 2 O 3 is +3 N 2 O 3 2 x +3(-2)=0 x=+3

Q. On heating, lead(II) nitrate gives a brown gas (A). The gas (A) on cooling changes to a colourless solid/liquid (B). (B) on heating with NO changes to a blue solid (C). The oxidation number of nitrogen in solid (C) is :

+5

+2

+4

+3

$P b (N O_{3})_{2} Δ P b O + (A) Brown gas 2 N O_{2} + \frac{1}{2} O_{2} (g)$
$N O_{2} (g) Cooling (B) N_{2} O_{4}$
$N_{2} O_{4} + NO Δ (C) Blue Solid N_{2} O_{3}$
O.S. of nitrogen in $N_{2} O_{3}$ is +3
$N_{2} O_{3} 2 x + 3 (- 2) = 0$
$x = + 3$

Q. On heating, lead(II) nitrate gives a brown gas (A). The gas (A) on cooling changes to a colourless solid/liquid (B). (B) on heating with NO changes to a blue solid (C). The oxidation number of nitrogen in solid (C) is :

+5

+2

+4

+3

Pb(NO3​)2​Δ​PbO+(A)Brown gas​2NO2​​+21​O2​(g) NO2​(g)Cooling​(B)N2​O4​​ N2​O4​+NOΔ​(C)Blue Solid​N2​O3​​ O.S. of nitrogen in N2​O3​ is +3 N2​O3​2x+3(−2)=0 x=+3

$P b (N O_{3})_{2} Δ P b O + (A) Brown gas 2 N O_{2} + \frac{1}{2} O_{2} (g)$
$N O_{2} (g) Cooling (B) N_{2} O_{4}$
$N_{2} O_{4} + NO Δ (C) Blue Solid N_{2} O_{3}$
O.S. of nitrogen in $N_{2} O_{3}$ is +3
$N_{2} O_{3} 2 x + 3 (- 2) = 0$
$x = + 3$