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Q.
On heating, lead(II) nitrate gives a brown gas (A). The gas (A) on cooling changes to a colourless solid/liquid (B). (B) on heating with NO changes to a blue solid (C). The oxidation number of nitrogen in solid (C) is :
$Pb(NO_3)_2 \xrightarrow{\Delta} PbO + \underset{\overset{\text{Brown gas}}{(A)}}{2NO_2} + \frac{1}{2}O_2(g)$
$NO_2(g) \xrightarrow{\text{Cooling}} \underset{(B)}{N_2O_4}$
$N_2O_4 + NO \xrightarrow{\Delta} \underset{\overset{\text{Blue Solid}}{(C)}}{N_2O_3}$
O.S. of nitrogen in $N _{2} O _{3}$ is +3
$N _{2} O _{3} 2 x +3(-2)=0$
$x=+3$