On decreasing the wavelength of incident light from 8000 mathringA to 4000 mathringA. The intensity of the scattered light in Rayleigh scattering will become times the initial scattered intensity.

Question

On decreasing the wavelength of incident light from 8000 mathringA to 4000 mathringA. The intensity of the scattered light in Rayleigh scattering will become times the initial scattered intensity. (A) 2 (B) 4 (C) 16 (D) 8

Tardigrade Admin · Accepted Answer

I propto (1/λ4) ⇒ (I f /Ii)=((λi/λ f ))4 =((8/4))4=24=16

Q. On decreasing the wavelength of incident light from $8000 \overset{˚}{A}$ to $4000 \overset{˚}{A}$ . The intensity of the scattered light in Rayleigh scattering will become ______ times the initial scattered intensity.

2

4

16

8

$I \propto \frac{1}{λ ^{4}}$
$\Rightarrow \frac{I _{f}}{I _{i}} = (\frac{λ _{i}}{λ _{f}})^{4}$
$= (\frac{8}{4})^{4} = 2^{4} = 16$

Q. On decreasing the wavelength of incident light from 8000A˚ to 4000A˚. The intensity of the scattered light in Rayleigh scattering will become ______ times the initial scattered intensity.

2

4

16

8

I∝λ41​ ⇒Ii​If​​=(λf​λi​​)4 =(48​)4=24=16

Q. On decreasing the wavelength of incident light from $8000 \overset{˚}{A}$ to $4000 \overset{˚}{A}$ . The intensity of the scattered light in Rayleigh scattering will become ______ times the initial scattered intensity.

$I \propto \frac{1}{λ ^{4}}$
$\Rightarrow \frac{I _{f}}{I _{i}} = (\frac{λ _{i}}{λ _{f}})^{4}$
$= (\frac{8}{4})^{4} = 2^{4} = 16$