On decreasing the wavelength of incident light from 8000 overset° A to 4000 overset° A, the intensity of the scattered light in Rayleigh scattering will become times the initial scattered intensity.

Question

On decreasing the wavelength of incident light from 8000 overset° A to 4000 overset° A, the intensity of the scattered light in Rayleigh scattering will become times the initial scattered intensity. (A) 2 (B) 4 (C) 16 (D) 8

Tardigrade Admin · Accepted Answer

I propto (1/λ 4) ⇒ (If/Ii)=((λi/λf))4 =((8/4))4=24=16

Q. On decreasing the wavelength of incident light from $8000 A^{\circ}$ to $4000 A^{\circ},$ the intensity of the scattered light in Rayleigh scattering will become _____ times the initial scattered intensity.

$2$

$4$

$16$

$8$

$I \propto \frac{1}{λ ^{4}}$
$\Rightarrow \frac{I _{f}}{I _{i}} = (\frac{λ _{i}}{λ _{f}})^{4}$
$= (\frac{8}{4})^{4} = 2^{4} = 16$

Q. On decreasing the wavelength of incident light from 8000A∘ to 4000A∘, the intensity of the scattered light in Rayleigh scattering will become _____ times the initial scattered intensity.

2

4

16

8

I∝λ41​ ⇒Ii​If​​=(λf​λi​​)4 =(48​)4=24=16

Q. On decreasing the wavelength of incident light from $8000 A^{\circ}$ to $4000 A^{\circ},$ the intensity of the scattered light in Rayleigh scattering will become _____ times the initial scattered intensity.

$2$

$4$

$16$

$8$

$I \propto \frac{1}{λ ^{4}}$
$\Rightarrow \frac{I _{f}}{I _{i}} = (\frac{λ _{i}}{λ _{f}})^{4}$
$= (\frac{8}{4})^{4} = 2^{4} = 16$