On an X temperature scale, water freezes at -125.0° X and boils at 375.0° X . On a Y temperature scale, water freezes at -70.0° Y and boils at -30.0° Y. The value of temperature on X -scale equal to the temperature of 50.0° Y on Y -scale is:

Question

On an X temperature scale, water freezes at -125.0° X and boils at 375.0° X . On a Y temperature scale, water freezes at -70.0° Y and boils at -30.0° Y. The value of temperature on X -scale equal to the temperature of 50.0° Y on Y -scale is: (A) 455.0° X (B) -125.0° X (C) 1375.0° X (D) 1500.0° X

Tardigrade Admin · Accepted Answer

(X -(-125)/500)=(Y-(-70)/40) For Y=50 X=1375.0° X

$455. 0^{\circ} X$

$- 125. 0^{\circ} X$

$1375. 0^{\circ} X$

$1500. 0^{\circ} X$

$\frac{X - ( - 125 )}{500} = \frac{Y - ( - 70 )}{40}$
For $Y = 50$
$X = 1375. 0^{\circ} X$

Q. On an X temperature scale, water freezes at −125.0∘X and boils at 375.0∘X. On a Y temperature scale, water freezes at −70.0∘Y and boils at −30.0∘Y. The value of temperature on X -scale equal to the temperature of 50.0∘Y on Y -scale is:

455.0∘X

−125.0∘X

1375.0∘X

1500.0∘X

500X−(−125)​=40Y−(−70)​ For Y=50 X=1375.0∘X

$455. 0^{\circ} X$

$- 125. 0^{\circ} X$

$1375. 0^{\circ} X$

$1500. 0^{\circ} X$

$\frac{X - ( - 125 )}{500} = \frac{Y - ( - 70 )}{40}$
For $Y = 50$
$X = 1375. 0^{\circ} X$