1. Tardigrade
  2. Question
  3. Physics
  4. On an X temperature scale, water freezes at -125.0° X and boils at 375.0° X . On a Y temperature scale, water freezes at -70.0° Y and boils at -30.0° Y. The value of temperature on X -scale equal to the temperature of 50.0° Y on Y -scale is:

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Q. On an $X$ temperature scale, water freezes at $-125.0^{\circ} X$ and boils at $375.0^{\circ} X .$ On a $Y$ temperature scale, water freezes at $-70.0^{\circ} Y$ and boils at $-30.0^{\circ} Y$. The value of temperature on $X$ -scale equal to the temperature of $50.0^{\circ} Y$ on $Y$ -scale is:

Thermal Properties of Matter

Solution:

$\frac{X -(-125)}{500}=\frac{Y-(-70)}{40}$
For $Y=50$
$X=1375.0^{\circ} X$