Of the isomeric hexanes, the isomers that give the minimum and maximum number of monochloro derivatives are respectively

Question

Of the isomeric hexanes, the isomers that give the minimum and maximum number of monochloro derivatives are respectively (A) 3-methylpentane and 2,3-dimethylbutane (B) 2, 3-dimethylbutane and n-hexane (C) 2, 2-dimethylbutane and 2-methylpentane (D) 2, 3-dimethylbutane and 2-methylpentane

Tardigrade Admin · Accepted Answer

The possible isomers of hexane are

Out of these structure (iii) and (i) have respectively minimum and maximum number of monochloroderivatives For structure (iii),

[Only 2 monochloroderivatives (minimum) are possible] For structure (i),

[5 monochloroderivatives (maximum) are possible]

Q. Of the isomeric hexanes, the isomers that give the minimum and maximum number of monochloro derivatives are respectively

$3$ -methylpentane and $2, 3$ -dimethylbutane

$2, 3$ -dimethylbutane and $n$ -hexane

$2, 2$ -dimethylbutane and $2$ -methylpentane

$2, 3$ -dimethylbutane and $2$ -methylpentane

$2$ -methylpentane and $2, 2$ -dimethylbutane

The possible isomers of hexane are

Out of these structure (iii) and (i) have respectively minimum and maximum number of monochloroderivatives
For structure (iii),

[Only 2 monochloroderivatives (minimum) are possible]
For structure (i),

[5 monochloroderivatives (maximum) are possible]

Q. Of the isomeric hexanes, the isomers that give the minimum and maximum number of monochloro derivatives are respectively

3-methylpentane and 2,3-dimethylbutane

2,3-dimethylbutane and n-hexane

2,2-dimethylbutane and 2-methylpentane

2,3-dimethylbutane and 2-methylpentane

2-methylpentane and 2,2-dimethylbutane